x1<x2<x3
解析分析:由于函數(shù)
的零點(diǎn)分別為x1,x2,x3,即函數(shù)令y1=2x,y2=lnx,
與函數(shù)y=-x的交點(diǎn)的橫坐標(biāo)分別為x1,x2,x3,作出函數(shù)的圖象,結(jié)合函數(shù)的圖象可判斷
解答:令y1=2x,y2=lnx,
,y=-x∵函數(shù)
的零點(diǎn)分別為x1,x2,x3函數(shù)令y1=2x,y2=lnx,
與函數(shù)y=-x的交點(diǎn)的橫坐標(biāo)分別作出函數(shù)的圖象,結(jié)合圖象可得x1<x2<x3故