x1<x2<x3
解析分析:由于函數(shù)

的零點分別為x1,x2,x3,即函數(shù)令y1=2x,y2=lnx,

與函數(shù)y=-x的交點的橫坐標(biāo)分別為x1,x2,x3,作出函數(shù)的圖象,結(jié)合函數(shù)的圖象可判斷
解答:令y1=2x,y2=lnx,

,y=-x∵函數(shù)

的零點分別為x1,x2,x3函數(shù)令y1=2x,y2=lnx,

與函數(shù)y=-x的交點的橫坐標(biāo)分別作出函數(shù)的圖象,結(jié)合圖象可得x1<x2<x3故