B
解析分析:先求出f(x)與g(x)的解析式,當(dāng)m≤0時(shí),顯然不成立;當(dāng)m>0時(shí),因?yàn)閒(0)=1>0,所以僅對(duì)對(duì)稱軸進(jìn)行討論即可.
解答:由題意可得
=2mx2+2mx-8x+1=2mx2-2(4-m)x+1,
=mx,當(dāng)m≤0時(shí),顯然不成立.當(dāng)m>0時(shí),因f(0)=1>0,當(dāng)-
=
≥0,即0<m≤4時(shí)結(jié)論顯然成立.當(dāng)-
=
<0時(shí),只要△=4(4-m)2-8m=4(m-8)(m-2)<0即可,即4<m<8.綜上可得,0<m<8故選B.
點(diǎn)評(píng):本題主要考查對(duì)二次函數(shù)圖象的理解,對(duì)于二次函數(shù)的圖象,一定要注意其開(kāi)口方向、對(duì)稱軸和判別式,體現(xiàn)了分類討論的數(shù)學(xué)思想,屬于中檔題.